In some cases where the direct comparison test is inconclusive, we can use the limit comparison test. Learn more about it here.
Practice this lesson yourself on KhanAcademy.org right now: https://www.khanacademy.org/math/ap-calculus-bc/bc-series/bc-comparison-tests/e/limit-comparison-test?utm_source=YT&utm_medium=Desc&utm_campaign=APCalculusBC
Watch the next lesson: https://www.khanacademy.org/math/ap-calculus-bc/bc-series/bc-comparison-tests/v/limit-comparison-test-example?utm_source=YT&utm_medium=Desc&utm_campaign=APCalculusBC
Missed the previous lesson? https://www.khanacademy.org/math/ap-calculus-bc/bc-series/bc-comparison-tests/v/comparison-test-convergence?utm_source=YT&utm_medium=Desc&utm_campaign=APCalculusBC
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Limit comparison test | Series | AP Calculus BC | Khan Academy
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28 thoughts on “Limit comparison test | Series | AP Calculus BC | Khan Academy”
Khan Academy has 1 million subs and this video has 0 comments? huh
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What is this called? Calculus?
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When you do math you use the left side of your brain, which always hurts when I use it too much. I've never felt a headache on the right side of my head, only the left. That's what makes me think is the reason I'm so lousy at math.
You're awesome dude!
Why did he divide the numerator and the denominator by 2^n at 5:45
take my tuition
Thank you sir! this helped lots!
what does he mean by positive and finite?
Thank you so much !
Thanks a bunch!! Really well done, i understood direct comparison test but LCT flew over my head until now.
Jesus man you're fucking awesome. Theres a lot of other good teachers on youtube, like professor leonard, and partcikjmt and such, but the one thing about your teaching is that you get the point across quickly. I dont have to spend 2.5 hours watching a whole lecture, or 6-7 different videos. You give us the theorems, maybe an example here and there, in like a 6 minute video. Thanks khan academy. Ya'll know whats up
How do we know 1/2^n converges?
But (1/2^n) doesn't Converge, it Diverges and is a Harmonic Series right?
are there more specific requirements for bn?
like if an is 1/2^n can i just set bn at 100^n?
I dont know when to use which method AHHH my exam is on saturday
If lim (an/bn) = t (t>1)
Then an > bn … If bn converges then it is not necessary for "an" to. Converge…
Pls can you prove the theorem?
your tutorials are amaazzinnggg 😀
the only thing that I fail to understand is when do we know when to put n=1 or n=0 below the sigma notation…
Can somebody please explain it to me 🙂
Thanks in advance:)
Plz give homework questions at the end of your videos plzzz
But what if the limit is zero when you do lim comparison. It's not positive??
So one use the limit comparison test when the direct comparison test gives you and inconclusive answers????
What if the limit comparison test equals 0?
For the second example can you use the traditional comparison test and say 1/1^n >= 1/(2^n – 1). Or is there something wrong there?
Your voice is so calming 🤍
Thank you :_)